0,2x^2+8,8=12

Solution for 0,2x^2+8,8=12 equation:

0.2x^2+8.8=12

We move all terms to the left:

0.2x^2+8.8-(12)=0

We add all the numbers together, and all the variables

0.2x^2-3.2=0

a = 0.2; b = 0; c = -3.2;
Δ = b2-4ac
Δ = 02-4·0.2·(-3.2)
Δ = 2.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2.56}}{2*0.2}=\frac{0-\sqrt{2.56}}{0.4}
=-\frac{\sqrt{}}{0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2.56}}{2*0.2}=\frac{0+\sqrt{2.56}}{0.4}
=\frac{\sqrt{}}{0.4}
$